Integrand size = 25, antiderivative size = 160 \[ \int \sec ^4(e+f x) \left (a+b (c \tan (e+f x))^n\right )^p \, dx=\frac {\operatorname {Hypergeometric2F1}\left (\frac {1}{n},-p,1+\frac {1}{n},-\frac {b (c \tan (e+f x))^n}{a}\right ) \tan (e+f x) \left (a+b (c \tan (e+f x))^n\right )^p \left (1+\frac {b (c \tan (e+f x))^n}{a}\right )^{-p}}{f}+\frac {\operatorname {Hypergeometric2F1}\left (\frac {3}{n},-p,\frac {3+n}{n},-\frac {b (c \tan (e+f x))^n}{a}\right ) \tan ^3(e+f x) \left (a+b (c \tan (e+f x))^n\right )^p \left (1+\frac {b (c \tan (e+f x))^n}{a}\right )^{-p}}{3 f} \]
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Time = 0.16 (sec) , antiderivative size = 160, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.240, Rules used = {3756, 1907, 252, 251, 372, 371} \[ \int \sec ^4(e+f x) \left (a+b (c \tan (e+f x))^n\right )^p \, dx=\frac {\tan ^3(e+f x) \left (a+b (c \tan (e+f x))^n\right )^p \left (\frac {b (c \tan (e+f x))^n}{a}+1\right )^{-p} \operatorname {Hypergeometric2F1}\left (\frac {3}{n},-p,\frac {n+3}{n},-\frac {b (c \tan (e+f x))^n}{a}\right )}{3 f}+\frac {\tan (e+f x) \left (a+b (c \tan (e+f x))^n\right )^p \left (\frac {b (c \tan (e+f x))^n}{a}+1\right )^{-p} \operatorname {Hypergeometric2F1}\left (\frac {1}{n},-p,1+\frac {1}{n},-\frac {b (c \tan (e+f x))^n}{a}\right )}{f} \]
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Rule 251
Rule 252
Rule 371
Rule 372
Rule 1907
Rule 3756
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \left (c^2+x^2\right ) \left (a+b x^n\right )^p \, dx,x,c \tan (e+f x)\right )}{c^3 f} \\ & = \frac {\text {Subst}\left (\int \left (c^2 \left (a+b x^n\right )^p+x^2 \left (a+b x^n\right )^p\right ) \, dx,x,c \tan (e+f x)\right )}{c^3 f} \\ & = \frac {\text {Subst}\left (\int x^2 \left (a+b x^n\right )^p \, dx,x,c \tan (e+f x)\right )}{c^3 f}+\frac {\text {Subst}\left (\int \left (a+b x^n\right )^p \, dx,x,c \tan (e+f x)\right )}{c f} \\ & = \frac {\left (\left (a+b (c \tan (e+f x))^n\right )^p \left (1+\frac {b (c \tan (e+f x))^n}{a}\right )^{-p}\right ) \text {Subst}\left (\int x^2 \left (1+\frac {b x^n}{a}\right )^p \, dx,x,c \tan (e+f x)\right )}{c^3 f}+\frac {\left (\left (a+b (c \tan (e+f x))^n\right )^p \left (1+\frac {b (c \tan (e+f x))^n}{a}\right )^{-p}\right ) \text {Subst}\left (\int \left (1+\frac {b x^n}{a}\right )^p \, dx,x,c \tan (e+f x)\right )}{c f} \\ & = \frac {\operatorname {Hypergeometric2F1}\left (\frac {1}{n},-p,1+\frac {1}{n},-\frac {b (c \tan (e+f x))^n}{a}\right ) \tan (e+f x) \left (a+b (c \tan (e+f x))^n\right )^p \left (1+\frac {b (c \tan (e+f x))^n}{a}\right )^{-p}}{f}+\frac {\operatorname {Hypergeometric2F1}\left (\frac {3}{n},-p,\frac {3+n}{n},-\frac {b (c \tan (e+f x))^n}{a}\right ) \tan ^3(e+f x) \left (a+b (c \tan (e+f x))^n\right )^p \left (1+\frac {b (c \tan (e+f x))^n}{a}\right )^{-p}}{3 f} \\ \end{align*}
Time = 1.14 (sec) , antiderivative size = 122, normalized size of antiderivative = 0.76 \[ \int \sec ^4(e+f x) \left (a+b (c \tan (e+f x))^n\right )^p \, dx=\frac {\tan (e+f x) \left (3 \operatorname {Hypergeometric2F1}\left (\frac {1}{n},-p,1+\frac {1}{n},-\frac {b (c \tan (e+f x))^n}{a}\right )+\operatorname {Hypergeometric2F1}\left (\frac {3}{n},-p,\frac {3+n}{n},-\frac {b (c \tan (e+f x))^n}{a}\right ) \tan ^2(e+f x)\right ) \left (a+b (c \tan (e+f x))^n\right )^p \left (1+\frac {b (c \tan (e+f x))^n}{a}\right )^{-p}}{3 f} \]
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\[\int \sec \left (f x +e \right )^{4} \left (a +b \left (c \tan \left (f x +e \right )\right )^{n}\right )^{p}d x\]
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\[ \int \sec ^4(e+f x) \left (a+b (c \tan (e+f x))^n\right )^p \, dx=\int { {\left (\left (c \tan \left (f x + e\right )\right )^{n} b + a\right )}^{p} \sec \left (f x + e\right )^{4} \,d x } \]
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Timed out. \[ \int \sec ^4(e+f x) \left (a+b (c \tan (e+f x))^n\right )^p \, dx=\text {Timed out} \]
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\[ \int \sec ^4(e+f x) \left (a+b (c \tan (e+f x))^n\right )^p \, dx=\int { {\left (\left (c \tan \left (f x + e\right )\right )^{n} b + a\right )}^{p} \sec \left (f x + e\right )^{4} \,d x } \]
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Exception generated. \[ \int \sec ^4(e+f x) \left (a+b (c \tan (e+f x))^n\right )^p \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \sec ^4(e+f x) \left (a+b (c \tan (e+f x))^n\right )^p \, dx=\int \frac {{\left (a+b\,{\left (c\,\mathrm {tan}\left (e+f\,x\right )\right )}^n\right )}^p}{{\cos \left (e+f\,x\right )}^4} \,d x \]
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